Sumivo · Electrical
PCB Trace Resistance Calculator
Estimate the DC resistance, voltage drop and power loss of a rectangular PCB copper trace.
01 / inputs
02 / result
RESISTANCE
49.557344 mΩ
- Resistance
- 49.557344 mΩ
- Voltage drop
- 0.049557 V
- Power loss
- 0.049557 W
- Cross-section
- 0.03479 mm²
Calculation trace
- 1.7241e-8 × (1 + 0.00393 × (20 − 20)) = 1.72410e-8 Ω·m1.72410e-8 Ω·mResistivity at temperature
- 1 mm × (1 oz × 34.79 µm) = 0.03479 mm²0.03479 mm²Cross-section
- 1.72410e-8 Ω·m × 0.1 m ÷ 3.47900e-8 m² = 49.557344 mΩ49.557344 mΩResistance
- 1 A × 0.049557 Ω = 0.049557 V0.049557 VVoltage drop
How it works
Estimate resistance, voltage drop and resistive power loss for one rectangular copper trace carrying DC. Cross-section A = width × thickness; R = ρL/A; voltage drop = IR; power loss = I²R. The engine uses ρ(T) = 1.7241 × 10⁻⁸ × [1 + 0.00393 × (T − 20)] Ω·m.
Assumptions & limits
- Enter length and width in mm, copper weight in oz/ft², current in A and copper temperature in °C. Length, width, copper weight and current must be finite and greater than zero. There is no fixed upper input limit, but calculations outside the finite positive numeric range are rejected.
- Temperature must be finite and give a positive temperature multiplier: 1 + 0.00393 × (T − 20) > 0 (approximately T > −234.453 °C). This is a mathematical guard, not a material operating-temperature specification. The page starts at 20 °C.
- This model converts 1 oz/ft² to 34.79 µm of thickness. This fixed conversion is a calculator assumption; enter the nominal copper weight, not a thickness in µm.
- The calculation uses a uniform cross-section and the temperature you supply. It does not solve self-heating, current capacity, AC impedance, vias, connectors or manufacturing variation.
Synthetic example
100 mm long, 1 mm wide, 1 oz/ft² copper, 2 A and 20 °C.
- Thickness = 1 × 34.79 = 34.79 µm. Area = 1 × 0.03479 = 0.03479 mm² = 3.479 × 10⁻⁸ m².
- At 20 °C the temperature multiplier is 1. R = (1.7241 × 10⁻⁸ × 0.1) ÷ (3.479 × 10⁻⁸) = 0.049557344… Ω.
- Voltage drop = 2 × R = 0.099114688… V. Power loss = 2² × R = 0.198229376… W.
49.557344 mΩ resistance, 0.099115 V drop and 0.198229 W loss (rounded).
Boundary case
A width of 0 mm is rejected because the cross-section would be zero. Current of 0 A is also rejected by this version, even though the ideal equations would give zero voltage drop and power loss. A temperature of −250 °C is rejected because the linear model would produce negative resistivity.
How to read the result
Resistance describes this trace segment only. Voltage drop is the voltage lost along it at the entered current; power loss is the electrical power dissipated in it. These outputs do not establish an allowable temperature rise or a safe current rating. A return trace or connector needs its own contribution.
Sources and what they support
- Conductor resistance R = ρL/A, voltage drop IR and resistive power I²R; the interpretations of voltage drop and power loss follow from these equations. IEC 60050 — International Electrotechnical Vocabulary (Electropedia)
- Annealed-copper reference resistivity at 20 °C and the 0.00393/°C linear temperature coefficient used in this model. IEC 60028 — International standard of resistance for copper
The copper-weight conversion, input guards and omitted effects above describe this implementation. The synthetic example is arithmetic under these assumptions, not a measured board or a fabrication tolerance.
FAQ
- What temperature should I enter?
- Enter the copper temperature for the condition you want to calculate. Ambient temperature is not automatically the trace temperature; this tool does not calculate their difference.
Related calculators
SOURCES
- International Electrotechnical Commission (IEC)IEC 60050 — International Electrotechnical Vocabulary (Electropedia) ↗
DC resistance of a conductor R = ρ·L/A and Ohm’s law (V = I·R, P = I²·R)
Accessed 2026-08-19
- International Electrotechnical Commission (IEC)IEC 60028 — International standard of resistance for copper ↗
Annealed copper (IACS) resistivity ρ₂₀ = 1.7241×10⁻⁸ Ω·m and temperature coefficient α = 0.00393/°C
Accessed 2026-09-02